How can you pass arguments to a shell script and access them within the script?

1 Answers
Answered by suresh

To pass arguments to a shell script and access them within the script, you can use the following method:

```html

Passing Arguments to a Shell Script

Passing Arguments to a Shell Script

To pass arguments to a shell script, you can simply provide them as space-separated values when executing the script from the command line. For example:

$ ./my_script.sh arg1 arg2 arg3

Within the shell script (my_script.sh in this example), you can access these arguments using positional parameters. The arguments are accessed as $1, $2, $3, and so on, corresponding to the position of the argument provided during the script execution.

Here is an example of how you can access and use the passed arguments within the shell script:

#!/bin/bash

echo "First argument: $1"
echo "Second argument: $2"
echo "Third argument: $3"

This script will display the values of the arguments passed to it when executed from the command line.

```

Answer for Question: How can you pass arguments to a shell script and access them within the script?